The midpoint of line segment RT is at (3.5, 2). If R is at (-3, 7), what are the coordinates of T?

(10,-3)

Explanation :

We know ,

If R (x1,y1)=(-3,7)

If T (x2,y2) = ?

Midpoint of line RT = (-3+x2)/2 , (7+y2)/2

(3.5,2) = (-3+x2)/2 , (7+y2)/2

So,

3.5 = (-3 + x2)/2 |1|

2 = (7 + y2)/2 |2|

Now , From eqn. |1|

3.5×2 = -3 + x2

7 + 3 = x2

10 = x2

From eqn. |2|

2×2 =7 + y2

4 - 7 = y2

-3 =y2

So,

T (x2,y2) = (10,-3)

hi,

i'm 75% sure the answer is 1,1 to both lines.

have a great day

#15. square

step-by-step explanation:

because quadrilatural (idk how to spell it) means somthing that is not 3d or like, equal sides (or somthing like that   you know what i meanz)

hope this halps!

bai!