What is the probability that a value picked at random from the standard normal distribution will be between -1.96 and 1.96?

P( -1.96 ≤ Z≤ 1.96) = 0.95

Step-by-step explanation:

Explanation:-

Given that the z -scores -1.96 and 1.96

we have to find   P( -1.96 ≤ Z≤ 1.96)

P( -1.96 ≤ Z≤ 1.96) = |A(1.96)+A(-1.96)|

                              = |A(1.96)+A(-1.96|   (∵A(-Z) = A(Z))

                            =  0.4750+0.4750

                            = 2×0.4750

                           = 0.95

The probability lies between  -1.96 to 1.96

P( -1.96 ≤ Z≤ 1.96) = 0.95

what is the starting amount? the question is not clear sorry.

step-by-step explanation:

constants mean the stopped points or the points on a graph that nothing is changing, hope this

step-by-step explanation: