The length of a rectangle is 4 meters less than twice its width. The are of a rectangle is 70m^2. Find the dimensions of the rectangle.

The length is 7 m

The width is 10 m

Step-by-step explanation:

length = x

width = 2x - 4

length * width = area

It is given that the area is 70

From there

x * (2x - 4) = 70

- 4x = 70

- 4x - 70 = 0

- 2x - 35 = 0

Now we have a quadratic equation, which is  a + bx + c = 0, where a 0

In this equation a = 1, b = -2 and c = -35

Discriminant (D) formula is b² - 4ac

D =  - 4 * 1 * (-35) = 144 > 0

This discriminant is more than 0, so there are two possible x

Their formulas are   and

=   = -5 < 0 (the length of the rectangle has to be more than 0, so we don't use this x)

= = 7 > 0 (this one is right)

Calculating the dimensions

length = x = 7 (m)

width = 2x - 4 = 2 * 7 - 4 = 10 (m)

any options?

step-by-step explanation:

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w