Write a system of linear inequalities so the points (1, 2) and (4, −3) are solutions of the system, but the point (−2, 8) is not a solution of the system.

step-by-step explanation:

∆abc has the points a(1, 7), b(-2, 2), and c(4, 2) as its vertices. formed with the point d(1, 2) as its third vertex, then ∆abd is triangle.

the answer is simply just 6n add the two together as they have an n

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol