How much charge is needed to repel another charge of 9.9 x 10^-6 N when they are 200m apart? Please help meee I really can't understand Coulomb's Law : (

The charge needed will be

Step-by-step explanation:

The equation of the electric force is given by:

We have the force  and the distance r = 200. k is the Coulomb constant. Q and q are the charges.

We assume we have the same charge of the particles,  so we have:

Therefore, the charge needed will be

I hope it helps you!

answer: c

(2, -4)

goes 7 to the

(9, 4)

easy

8(4)^8=72^feet to say that the total can conclude to 8(4) which as you know would mean 8 x 4. that equals 32w. 32^ could make a 72 answer as well. but your coefficent will remain w so your answer is 72w.

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