If x=6 and y=2 then the value of 3x^2-4(2y-4/12) +8

3x^2−8y+28/3

Step-by-step explanation:

3x^2-4(2y-4/12) +8

Reduce the fraction 4/12 to lowest terms by extracting and canceling out 4.

3x^2-4(2y-1/3) +8

Use the distributive property to multiply −4 by 2y - 1/3

3x^2-8y+4/3+8

Add 4/3 and 8 to get 28/3

3x^2−8y+28/3

what is the original number? you forgot to add it.