A flying squirrel's nest is 12 feet high in a tree. From its nest, the flying squirrel glides 20 feet to reach an acorn that is on the ground. How far is the acorn from the base of the tree?

16 feets

Step-by-step explanation:

Distance (D) of acorn from base of tree :

Using Pythagoras :

Adjacent = sqrt[(hypotenus² - opposite²)]

Hence,

D = sqrt[(20² - 12²)]

D = sqrt[(400 - 144)]

D = sqrt(256)

D = 16 feets

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

40 x 50 = 2000

step-by-step explanation: