A line is parallel to y = 3x + 5 and intersects the point (-2, 6). What is
the equation of this parallel line?
Start by entering this into point-slope form.
y- [?] = [](x
](x-[]).

Im not like 100% sure but i think you answer is

y-6=3[x-(-2)]

y=6+3x+6

y=3x+12

And i believe that this is parallel to y

Step-by-step explanation:

Parallel lines have same slope

Given line

The line that passes through (-2, 6) and with the slope of 3 is:

Convert the equation into slope-intercept form:

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.