Anthony has $11,600 in his account and earns $700 per month. He spends $8,000 on a car and has other expenses totaling $900 per month. How many months will go by before Anthony runs out of money?

216 Months

Step-by-step explanation:

First find how much money he looses per month: 0+700-8000= -7300 on the first month. So 11600-7300=4300.

Then, he starts loosing $200 dollars per month because 900-700=200.

So 4300/20=215. So 215+1=216 months before Anthony runs out of money.

16 months

Step-by-step explanation:

8000-11600=3600

700-900= -200monthly

200divide 3600= 16 months

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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