Answer fast! Will mark brainliest-- Reflect quadrilateral SQRT over the y-axis. Then translate the new quadrilateral 3 units to the right. What are the coordinates of the vertices of the final image? A. S’(-2, 3), Q’(1, 2), R’(-3, -2), T’(-3, 1)
B. S’ (0, 1), Q’(1, -5), R’(7, -4), T’(6, -1)
C. S’(8, 3), Q’(5, 2), R’(6, -2), T’(9, -1)
D. S’(5, 3), Q’(2, 2), R’(3, -2), T’(9, -1)

i dont know

Step-by-step explanation:

i think the answer for the new coordinates is C but it doesnt make sence

Step-by-step explanation:

i cant tell for sure because their isnt a picture of where the quadrilaterel is im sorry

D).S’(5, 3), Q’(2, 2), R’(3, -2), T’(9, -1) should be the correct answer.

Step-by-step explanation:

I took the test on edg.

idk i would have to be there to under stand it

step-by-step explanation:

idk i would have to be there to under stand it

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50