Write the equation of the line perpendicular to y = 6/5x + 4/5 that passes through the point (-3,2).

The equation of the perpendicular line of the given line is

Step-by-step explanation:

Step(i):-

Given the equation of the line

cross-multiplication, we get

       5y = 6x +4

The equation of the straight line is 6x - 5y +4=0

The equation of the perpendicular line to the given line is

                        b x - ay +k=0

The equation of the perpendicular line to the given line is   -5x-6y +k=0

This line passes through the point (-3,2)

    ⇒       - 5(-3) -6(2)+k=0

     ⇒       15 -12 +k=0

     ⇒              3 +k=0

       ⇒              k =-3

Step(ii):-

The equation of the perpendicular line is

                                  -5x-6y-3=0

                                  5x + 6y +3 =0

                                        6y = -5x-3

Final -

The equation of the perpendicular line of the given line is

a4 - 3a2 - 1

step-by-step explanation:

step   1   :

equation at the end of step   1   :

  ((a4) -   3a2) -   1

step   2   :

trying to factor by splitting the middle term

2.1     factoring   a4-3a2-1  

the first term is,   a4   its coefficient is   1 .

the middle term is,   -3a2   its coefficient is   -3 .

the last term, "the constant", is   -1  

160 cm

step-by-step explanation:

you have to add all the sides together