The roots a and ß of the quadratic equation x2-5x+3(k-1)=0 are such that a- B=1. Find the value k.​

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Step-by-step explanation:

let x=1

now,

(1)×2-5×(1)+3(k-1)=0

2-5+3(k-1)=0

2-5+3k-3=0

2-8+3k=0

-6+3k=0

3k=6

k= 2

option: d is correct

step-by-step explanation: