Consider an experiment that has N outcomes E1 E2 ...En where it is known that outcomes ej + 1 is twice as likely as the outcome is ej for: j=1,2,N-1. let
Ek={E1,E2Ek} show that
P(Ek)=(2^k-1)/(2^N-1)​

its kind of blurry. can you put a clearer pic?

step-by-step explanation:

600,000,000,000, or 6e14

step-by-step explanation:

3

step-by-step explanation:

m∠abd = m∠dbc

step-by-step explanation:

given : ab bisects ∠dbc

as we know that bisection means ab divides   ∠dbc   in two equal angles named as   ∠dba and   ∠abc

so, m∠abd = m∠dbc  

because ab bisects ∠dbc.

hence , the first statement m∠abd = m∠dbc is true.