Find five solutions for the linear equation 2/4 X + Y =22. Help!!

x                    the link is https://socratic.org/questions/how-do-you-solve-the-      system-of-linear-equations-5x-4y-7-2y-6x-22

=

3

and

y

=

2

.

Explanation:

5

x

−

4

y

=

7

2

y

+

6

x

=

22

From the second equation, we can determine a value for

4

y

.

2

y

+

6

x

=

22

Multiply all terms by

2

.

4

y

+

12

x

=

44

Subtract

12

x

from both sides.

4

y

=

44

−

12

x

In the first equation, replace

4

y

with

(

44

−

12

x

)

.

5

x

−

4

y

=

7

5

x

−

(

44

−

12

x

)

=

7

Open the brackets and simplify. The product of two negatives i a positive.

5

x

−

44

+

12

x

=

7

17

x

−

44

=

7

Add

44

to both sides.

17

x

=

51

Divide both sides by

17

.

x

=

3

In the second equation, substitute

x

with

3

.

2

y

+

6

x

=

22

2

y

+

(

6

×

3

)

=

22

2

y

+

18

=

22

Subtract

18

from both sides.

2

y

=

4

Divide both sides by

2

.

y

=

2

x

=

3

and

y

=

2

.

Explanation:

5

x

−

4

y

=

7

2

y

+

6

x

=

22

From the second equation, we can determine a value for

4

y

.

2

y

+

6

x

=

22

Multiply all terms by

2

.

4

y

+

12

x

=

44

Subtract

12

x

from both sides.

4

y

=

44

−

12

x

In the first equation, replace

4

y

with

(

44

−

12

x

)

.

5

x

−

4

y

=

7

5

x

−

(

44

−

12

x

)

=

7

Open the brackets and simplify. The product of two negatives i a positive.

5

x

−

44

+

12

x

=

7

17

x

−

44

=

7

Add

44

to both sides.

17

x

=

51

Divide both sides by

17

.

x

=

3

In the second equation, substitute

x

with

3

.

2

y

+

6

x

=

22

2

y

+

(

6

×

3

)

=

22

2

y

+

18

=

22

Subtract

18

from both sides.

2

y

=

4

Divide both sides by

2

.

y

=

2

Step-by-step explanation: