Manny makes dinner using 1 box of pasta and 1jar of sauce .If pasta is sold in oackage if 6 boxes and sauce is sold in in packages of 3 jjara what is the least number of dinners that manny can make without any supplies leftover

The least number of dinners that manny can make without any supplies leftover is 6 dinners

Step-by-step explanation:

Dinner = 1 box of pasta + 1jar of sauce

pasta is sold in package of 6 boxes

sauce is sold in in packages of 3

jars

what is the least number of dinners that manny can make without any supplies leftover?

Find the lowest common multiple of 6 boxes and 3 jars

6 boxes = 6, 12, 18, 24, 30, 36, 42,48

3 jars = 3, 6, 9, 12, 15, 18, 21, 24, 27, 30

The lowest common multiple of 6 boxes and 3 jars = 6

The least number of dinners that manny can make without any supplies leftover is 6 dinners

Using:

Pasta = 6 dinners / 6 boxes

= 1 package

Pasta = 1 package

Sauce = 6 dinners / 3 jars

= 2 package

Sauce = 2 package

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

step-by-step explanation:

graph using a few selected

x         y

-1       15

0         6

1         2.4

2       0.96