How does the mean absolute deviation (MAD) of the data in set 1 compare to the mean absolute deviation of the data in set 2? Answer correctly im timed. the answer is not: The MAD of set 1 is 5 less than the MAD of set 2.
Set 1: 12, 8, 10, 50
Set 2: 13, 9, 8
The MAD of set 1 is 13 less than the MAD of set 2.
The MAD of set 1 is 13 more than the MAD of set 2.
The MAD of set 1 is 2 more than the MAD of set 2.
The MAD of set 1 is 2 less than the MAD of set 2.

{Hello Kirito here your answer is!!}

The Mean Absolute Deviation of Set 1 is 13 more than the mean absolute deviation of Set 2.

Step-by-step explanation:

Set 1: 12, 8, 10, 50

Set 2: 13, 9, 8

Step 1:We determine the mean for each set

Mean of Set 1:

Mean of Set 2:

Step 2: We determine the mean absolute deviation (MAD) of the data in each set.

M.A.D of Set 1:

Mean of Set 2:

The Mean Absolute Deviation of Set 1 is 13 more than the mean absolute deviation of Set 2.

Theres a guy above my awnser who didn't specify what the awnser is.

Step-by-step explanation:

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i