What is the correct method of solving the equation x/3-6=9 for x? A. Add 6 to both sides of the equation, and then divide both sides of the equation by 3.
B. Add 6 to both sides of the equation, and then multiply both sides of the equation by 3.
C. Subtract 6 from both sides of the equation, and then divide both sides of the equation by 3.
D. Subtract 6 from both sides of the equation, and then multiply both sides of the equation by 3.

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.

idk

step-by-step explanation: