Five times a number plus four times a second number is 20. Four times the first number added by two times the second number is 16. Write the
system of equations for this situation. *

first number is 4

second number is 0

Step-by-step explanation:

y = 1st number

x = 2nd number

system of equations:

5y + 4x = 20

4y + 2x = 16

I multiplied the second equation by -2 to eliminate the 'x-values'

-2(4y + 2x = 16)  =                 -8y - 4x = -32

now add to 1st equation:     5y + 4x = 20

                                              -3y = -12

y = 4

solve for 'x':

5(4) + 4x = 20

20 + 4x = 20

4x = 0

x = 0

the answer is true.

step-by-step explanation:

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation: