A CBS News poll asked 606 randomly selected women and 442 randomly selected men, "Do you think putting a special tax on junk food would encourage more people to lose weight?" 170 of the women and 102 of the men said "Yes." A 99% confidence interval for the difference (Women – Men) in the true proportion of people in each population who would say "Yes" is –0.020 to 0.120. a. Does the confidence interval provide convincing evidence that the two population proportions are different? Explain your answer.
b. Does the confidence interval provide convincing evidence that the two population proportions are equal? Explain your answer.

Follows are the solution to the given question:

Step-by-step explanation:

In point a:

The confidence interval will not provide convincing proof that only the two population prolongations differentiate because a 99 percent confidence interval for both the difference throughout the true promotion around -0.020 and 0.120 is included 0.

In point b:

This confidence interval gives strong evidence also that two population proportions were identical because there is a confusion interval of 99 percent between  -0.020 and 0.120 for the difference in the true percentage of the population that say "Yes".

b

step-by-step explanation:

u take $75 minus $60.the anwer/original($75)multiply by 100