Perform this operation and report the answer to the correct number of significant figures: what is the mass of a cube of aluminum that is 4.0 cm on each edge? the density of aluminum is 2.7 g/cm^3. show all calculations leading to an answer.

The answer is 172.8 g.

The volume of the cube (V) is:
V = a³            (a - the side of the cube)

The density (D) is quotient of mass (m) and volume (V):
D = m/V = m/a³
⇒ m = D · a³


It is given:
D = 2.7 g/cm³
a = 4 cm
Therefore:
m =  D · a³ = 2.7 · 4³ = 172.8 g

Hmmm i had this before , give me a sec