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Mathematics, 12.02.2021 02:00 rschaum08

Given: \angle BAC \cong \angle ACD∠BAC≅∠ACD and \angle ADB \cong \angle DBC.∠ADB≅∠DBC. Prove: ABCDABCD is a parallelogram.

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Given: \angle BAC \cong \angle ACD∠BAC≅∠ACD and \angle ADB \cong \angle DBC.∠ADB≅∠DBC.

Prove: ABC

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Given: \angle BAC \cong \angle ACD∠BAC≅∠ACD and \angle ADB \cong \angle DBC.∠ADB≅∠DBC. Prove: ABCDA...
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