What is the equation of the line containing the points (5,2), (10,4), and (15, 6)?
O A. y= x
O B. y = -x+1
C. y = x-3

y=2/5x+4 1/5

Step-by-step explanation:

first you have to find y=mx+b so to find m you use the equation

y2-y1/x2-x1

so pick 2 points on the line such as 4-2/10-5 and you get 2/5

next plug in on point to the equation y=2/5x+b

so 5=2/5 (2) + b; to find b

5=4/5 +b

minus 4/5 on each side

4 1/5 = b

so you get the equation y=2/5x+4 1/5

then plug in the third point

hope that helps

y=2/5x

Step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204