The length of a rectangle is 3ft less than twice the width, and the area of the rectangle is 77ft^(2). Find the dimensions of the rectangle

Dimensions of the rectangle are 5.5ft and 14 ft

Step-by-step explanation:

Let x = width in ft

    y= length in ft

Given, y = 3+2x (1)

Area = xy = 77 ft2

Using (1) to replace y

3x+2x2=77

2x2+3x-77=0

Solve this quadratic equation, a=2, b=3, c=-77

x=(-3(+or-)sqrt(32-4*2*(-77)))/(2*2)

 = (-3 (+ or -) sqrt(9+616))/4

 = (-3 (+ or -) sqrt(625))/4

 = (-3 (+ or -) 25)/4

x = (-3+25)/4   or x = (-3-25)/4

  = 22/4                 =  -28/4

x  = 5.5               x  = -7

x is the length and can't be negative. so, proceed with x= 5.5

xy = 77

y = 77/5.5  = 14

Dimensions of the rectangle are 5.5ft and 14 ft

(Check: 2* 5.5 + 3 = 11+3 = 14)

(x, y)→(x − 8, y − 7)

step-by-step explanation:

enjoy!

answer is b

step-by-step explanation: