For* 15-16 find the number of sides if a polygon has the given measure for each interior angle, 170
15 n=a) 21 b) 24 c) 30 4) 36 )42
162
16. n = a) 16 D) 20 c)24 d) 28 ) 32
60
For #17 - 24. determine the sum of the interior angles then find the missing angle.
17. sum = a) 120 b) 140 c) 160
d) 180 e) 200
18 x= a) 40 b) 50 c)60
d) 70 e) 80
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70
120
19 Sum = a) 300 b) 330 C) 360 d) 380 e) 410
20 X a) 50 b) 60 с) 75 d) 80 e) 85
90
90
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15. d) 36

16. b) 20

17. d) 180

18. b) 50

19. c) 360

20. b) 60

Step-by-step explanation:

To find the number of sides a polygon has giving an interior angle, use the equation:

(number of sides - 2)*180/(number of sides) = measure of interior angle

15. (n = number of sides)

((n-2)*180)/n = 170

180n-360 = 170n

10n = 360

n = 36 (d)

16. (n = number of sides)

((n-2)*180)/n = 162

180n-360 = 162n

18n = 360

n = 20 (b)

17. The sum of the interior angles of a triangle is always 180 (d)

18. 180-60-70 = 50 (b)

19. The sum of the interior angles of a quadrilateral is always 360 (c)

20. 360-120-90-90 = 60 (b)

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

y -5 = (-1/4)(x + 8)

step-by-step explanation: