Trapezoid jklm is shown on the coordinate plane below:

trapezoid jklm on the coordinate plane with ordered pairs at j negative 2, 1, at k 1, 1, at l 3, negative 2, at m negative 4, negative 2.

if trapezoid jklm is translated according to the rule (x, y) _ (x + 5, y _ 4), what are the coordinates of point l'?

Well, if I'm reading this correctly, your first trapezoid has coordinates:
J(-2, 1), K(1, 1), L(3, -2), and then M(-4, -2).
Now it gives you the transition equation for how the trapezoid would move which is: (x, y) -> (x + 5, y - 4)
Since you are looking for L, simply place L's coordinates inside:
L = (3 + 5, -2 - 4) -
Now solve it. L = (8, -6) -
This should be the new set of coordinates for L.

A= r2 × 3.14 11×11 ↓ ↓ 121 × 3.14 = 379.94 → 379.9