Determine whether each of the properties described applies to volumetric or graduated glassware. a. Used for applications in which great accuracy is needed
b. Capable of measuring a range of volumes of liquid
c. Designed to measure one specific volume of liquid

a. volumetric glassware

b. Graduated glassware

c. volumetric glassware

Step-by-step explanation:

The graduated glassware and the volumetric glassware is the factory  calibrated used to deliver such as the graduated cylinders and pipettes and it contains the volumetric flask of a known amount of the liquid.

A volumetric glassware is a type of the laboratory flask and a graduated glassware is mostly of the cylinder shape and is also known as the measuring cylinder.

In the context,

a). The volumetric glassware is used in the applications where much accuracy is needed to perform the experiment.

b). Graduated glassware is used for measuring a wide range of volume of the liquid used in the laboratory,

c). The volumetric glassware is used to measure one specific amount of the volume of the liquid to be used.

e

step-by-step explanation:

an equation by definition has to have two or more variables (x and 2 in this case)

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!