Sections 10.1-10.3 Review A bag contains 1 green, 4 red and 5 yellow balls. Two balls are selected at
random. Find the probability if there is no replacement of P(1 red and 2 yellow).

20/45

6/45

Step-by-step explanation:

A bag contains 1 green, 4 red, and 5 yellow balls. Two balls are selected at random. Find P( 1 red and 1 yellow) and P(2 red).

# of red/yellow pairs: 4*5 = 20

# of random pairs: 10C2 = 45

P(1red & 1yellow) = 20/45

# of red pairs: 4C2 = 6

# of random pairs = 45

P(2 red) = 6/45

the answer is y = 11.54

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