Mathematics, 03.02.2020 05:47 yollo74

In a manufacturing process that laminates several ceramic layers, 1% of the assembles are defective. assume that the assemblies are independent.
a) what is the mean number of assemblies that need to be checked to obtain 5 defective assemblies?
b) what is the standard deviation of the number of assemblies that need to be checked to obtain 5 defective assemblies?
x = number of assemblies needed to obtain 5 defectives.

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Answers

There are several information's already given in the question. based on those information's, the answer can be easily deduced.

a. It is already given that 1% are defective. It is required to find the number that is needed to be checked to get 5 defective products.
Then
1% of X = 5
0.01X = 5
x = 5/0.01
= 500

b. σ = square root [(n^2−1)/12]
= square root [(250000 - 1)/12]
= square root [249999/12]
= square root (20833.25)
= 144.34
= 144
I hope the procedure is clear enough for you to understand. I also hope that this is the answer that you were looking for and the answer has actually come to your desired help.

Answer from: Quest

cant open file sorry!

step-by-step explanation:

Answer from: Quest

when functions are first introduced, you will probably have some simplistic "functions" and relations to deal with, usually being just sets of points. these won't be terribly useful or interesting functions and relations, but your text wants you to get the idea of what the domain and range of a function are. small sets of points are generally the simplest sorts of relations, so your book starts with those.

step-by-step explanation:

state the domain and range of the following relation. is the relation a function?

{(2, –3), (4, 6), (3, –1), (6, 6), (2, 3)}

the above list of points, being a relationship between certain x's and certain y's, is a relation. the domain is all the x-values, and the range is all the y-values. to give the domain and the range, i just list the values without duplication:

domain: {2, 3, 4, 6}

range: {–3, –1, 3, 6}

(it is customary to list these values in numerical order, but it is not required. sets are called "unordered lists", so you can list the numbers in any order you feel like. just don't duplicate: technically, repetitions are okay in sets, but most instructors would count off for this.)

while the given set does indeed represent a relation (because x's and y's are being related to each other), the set they gave me contains two points with the same x-value: (2, –3) and (2, 3). since x = 2 gives me two possible destinations (that is, two possible y-values), then this relation is not a function.

note that all i had to do to check whether the relation was a function was to look for duplicate x-values. if you find any duplicate x-values, then the different y-values mean that you do not have a function. remember: for a relation to be a function, each x-value has to go to one, and only one, y-value.

state the domain and range of the following relation. is the relation a function?

{(–3, 5), (–2, 5), (–1, 5), (0, 5), (1, 5), (2, 5)}

i'll just list the x-values for the domain and the y-values for the range:

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