If the dimensions of a cylinder are doubled, then its volume is quadrupled. which i know is false.
but my question is what is the dimensions of its volume going to be, doubled? i'm getting ready for my test.

Suppose we have a cylinder with radius r1 and height h1. The volume of this cyliner would be calculated as:

V1 = pi(r1^2)h1

If the measurements are being doubled then r2=2r1 and h2=2h1. The volume would change as follows:

V2 = pi(r2^2)h2

V2 = pi((2r1)^2)2h1

V2 = pi(4)(r1)^2)2h1

V2 =8 pi(r1)^2)h1
V2 = 8 V1

Suppose we have a cylinder with radius r1 and height h1. The volume of this cyliner would be calculated as:

V1 = pi(r1^2)h1

If the measurements are being doubled then r2=2r1 and h2=2h1. The volume would change as follows:

V2 = pi(r2^2)h2

V2 = pi((2r1)^2)2h1

V2 = pi(4)(r1)^2)2h1

V2 =8 pi(r1)^2)h1
V2 = 8 V1

Ibelieve the answer is c