Find the minimum y-value on the graph y=f(x)
f(x)= x^2+4x-5

There are two ways to solve the problem: using calculus and algebra. For this, I'll be using the algebraic way. The function is parabolic, thus the minimum value is the ordinate of the vertex. Using completing the square, we could get the vertex of the parabola.

y = x^2 + 4x - 5y = x^2 + 4x + 4 - 5 - 4y = (x + 2)^2 - 9Vertex is (-2, -9). 

Therefore, the minimum value is -9.

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Iam guessing c. or d.