The average weight of ten bulls is 500kg and the standard deviation of the weight is 30kg. What would be the weight of a bull that is 6 standard deviations above the mean weight

680kg

Step-by-step explanation:

The average weight of ten bulls is 500kg and the standard deviation of the weight is 30kg. What would be the weight of a bull that is 6 standard deviations above the mean weight

The formula to solve for the weight that is 6 standard deviation above the mean weight =

μ + 6σ = w

Where

μ = Mean weight = 500kg

σ = Standard deviation = 30kg

Hence:

w = 500kg + 6(30kg)

w = 500kg + 180kg

w = 680kg

Therefore, the weight of a bull that is 6 standard deviations above the mean weight is 680 kg

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

b. an equilateral triangle inscribed in a circle

step-by-step explanation:

we are given the figure of two circles having a triangle inside.

now, we know that,

"when a figure is lying inside an another figure, then the outside figure is known as circumscribed figure and the figure lying inside is referred to as the inscribed figure".

as we see that, the circles are containing the triangle completely.

thus, the circles are the circumscribed figures and the triangle is the inscribed figure.

hence, we get, 'an equilateral triangle is inscribed in a circle'.