Which of the following systems of inequalities has point C as a solution? Two linear functions f of x equals 3 times x plus 4 and g of x equals negative one half times x minus 5 intersecting at one point, forming an X on the page. A point above the intersection is labeled A. A point to the left of the intersection is labeled B. A point below the intersection is labeled C. A point to the right of the intersections is labeled D. f(x) ≤ 3x + 4 g of x is less than or equal to negative one half times x minus 5 f(x) ≥ 3x + 4 g of x is less than or equal to negative one half times x minus 5 f(x) ≤ 3x + 4 g of x is greater than or equal to negative one half times x minus 5 f(x) ≥ 3x + 4 g of x is greater than or equal to negative one half times x minus 5

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for

its 50 miles away from the starting point

you ignore the remainder, therefore the answer is y = x+2

step-by-step explanation:

you have to divide the denominator by the numerator. you can use synthetic division or long division.

[-5] .     1 .     7 .     11

x + 2 + 1/x+5