Plz Hurry Jeremy constructed this solid by combining two rectangular prisms and a square pyramid. A rectangular prism with a length of 6 meters, width of 14 meters, and height of 2 meters. A rectangular prism with a length of 5 meters, width of 8 meters, and height of 3 meters. A square pyramid with a base of 6 meters by 6 meters and triangular sides with a height of 7 meters.

What is the surface area of this figure?

square meters

320

322

368

386

Jeremy constructed this solid by combining two rectangular prisms and a square pyramid.

A rectangular prism with a length of 6 meters, width of 14 meters, and height of 2 meters. A rectangular prism with a length of 5 meters, width of 8 meters, and height of 3 meters. A square pyramid with a base of 6 meters by 6 meters and triangular sides with a height of 7 meters.

What is the surface area of this figure?

square meters

320

322

√368

386

Step-by-step explanation:

it was that because you have to figure out the numbers and multiply all the number and you get the number 368

I can confirm that it is indeed C

Step-by-step explanation:

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v