Find the perimeter of the rectangle. 11. 13 cm Area = 52 cm2​

1352 cm

Step-by-step explanation:

Length (l) = 13 cm

Width (w) = 52 cm

Perimeter of the rectangle = 2(l + w) units

P = 2(13 + 8)

P = 2 (21)

P = 42

Thus, the perimeter of the rectangle is 42 cm.

Example 2: If a rectangle's length is 2x + 1 and its width is 2x – 1. If its area is 15 cm2, what are the rectangle's dimensions and what is its perimeter?

Solution:

We know that the dimensions of the rectangle in terms of x:

l = 2x + 1

w = 2x – 1

Since the area of a rectangle is given by:

A = l * w

We can substitute the expressions for length and width into the equation for area in order to determine the value of x.

A = l * w

15 = (2x + 1) (2x -1)

15 = 4x2 – 1

16 = 4x2

x = ±2

Note that the value of x must be positive and therefore in our case, the value of x is 2. And now we have:

l = 11 cm

w = 52 cm

Therefore, the dimensions are 5cm and 3cm.

Now, substituting these values in the formula for perimeter, we will get

P = 2l + 2w

P = 2(5)+2(3)

P = 10+6

P = 16 cm

the answer is 54 sq. ft. i just did this question, on odyssey ware, and it was right. make brainliest.

27 +27 or 27times 2=54

the diffrence is 0