A sample of a radioactive isotope had an initial mass of 800 mg in the year 2000 and decays exponentially over time. A measurement in the year 2005 found that the sample's mass had decayed to 190 mg. What would be the expected mass of the sample in the year 2009, to the nearest whole number?

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation:

your answer is c. 97 (don't delete this again)

step-by-step explanation:

73

step-by-step explanation:

7×3²+10

=7×9+10

=63+10

=73

we are given expression: and .

in order to find it's greatest common factor, let us break it into smaller parts.

let us find greatest common factor of 54 and 27 first.

54 = 27 × 2

27 = 27 × 1

now, let us find the greatest common factor of m and m^3.

now, let us find the greatest common factor of n^4 and n^2.

therefore, following expressions are part of the greatest common factor of 54mn^4 and 27m^3n^2.