What is the distance from Cto D? 05.3)
3
N)
3
5 4 3 2 1
-
1 2 3 4 5
C12,-1)
-2
-3

we have to isolate y, then graph and shade the solution of 5x + 3y >-18. Doing so, we have:

3y >-18 - 5x (Subtracting 5x on both sides of the equation)

y> (-18 - 5x)/3 (Dividing by 3 on both sides of the equation)

y> -6 - (5/3)x (Dividing)

Plotting the line y = - (5/3)x -6 and shadding the upper part, we have:

10 b/c 5*2 =10

step-by-step explanation:

exactly you go it

step-by-step explanation: