1. Consider the functions g(x) = =(19
and h(x) = -1
CU. 2.5, 2.25, 1.5 points)
a) The points given below in the first column)
belong to g(x) = Perform two
transformations (show tracking of ordered pairs) to
0) =()
b) Sketch a graph of y = g(x) and y=h(x).
Include each horizontal asymptote as a dashed line.
Approximate point placement where necessary.
get points that belong to h(x) = -1.
7.
5-
4
3
(-2,4) →( , )+(, )
(-1,2)-( , ) →( , )
(0,1)+( , )
2
9
-5
23
6
7
-5
(1,1)>( . )-( ;)
(2,4)=( , )(, )
->

i am currently in the exact same situation rn. algebra2/adv algebra is killing

step-by-step explanation:

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

english, cause i can’t you