A rectangular dining room has an area of 20 square meters. It's perimeter is 18 meters. What are the dimensions of the dining room?

The dimensions are:

Length = 5m and Width = 4m

Or

Length = 4m and Width = 5m

Step-by-step explanation:

A rectangular dining room has an area of 20 square meters. It's perimeter is 18 meters. What are the dimensions of the dining room?

Area of a rectangle = Length × Width

= LW = 20 m²

Perimeter of a rectangle =

2L + 2W = 18 m

Hence:

LW = 20 Equation 1

L = 20/W

2L + 2W = 18 Equation 2

We substitute

20/W for L in Equation 2

2(20/W) + 2W = 18

40/W + 2W = 18

Multiply through by W

40 + 2W² = 18W

2W² - 18W + 40 = 0

2W² - 10W - 8W + 40 = 0

(2W - 8 )(W - 5) = 0

2W - 8 = 0

2W = 8 , W = 8/2 = 4m

W - 5 = 0

W = 5m

W = 4m or 5 m

Solving for L

When W = 5 m

L = 20/W

L = 20/5

L = 4m

When W = 4m

L = 20/W

L = 20/4

L = 5m

Therefore, the dimensions are:

Length = 5m and Width = 4m

Or

Length = 4m and Width = 5m

well the 1 and -1 are always after the 0 and the 0 is inthe middle. s thats what i would guess. but i dont know what a slope of 2 is sorry

step-by-step explanation: