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The areas of the squares adjacent to two sides of a right triangle are shown below.

35
units
2
35 units
2

50
units
2
50 units
2

?
units
2
? units
2

What is the area of the square adjacent to the third side of the triangle?

units
2
2
squared

50 units.

Step-by-step explanation:

i dont know

step-by-step explanation:

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.