If P(6, -2), Q(-2, 8), R(-4, 3), and S(-9, y), find the value of y so that PQ is perpendicular to RS

Step-by-step explanation:

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong