A scuba diver dove 40 feet below the surface. He swam up 12 feet to see a unique fish. He followed the fish down 8 feet. Then he followed the fish up 27 feet. How far below the surface is the diver now?

9 feet below the surface.

Step-by-step explanation:

The scuba diver starts 40 ft below the surface. We can represent the position of the scuba diver as:

Position = -40ft

Where the negative sign is because it is below the surface of the water, so

"He swam up 12 feet to see a unique fish."

Now we need to add 12ft

Then his new position is:

Position = -40ft + 12 ft = -28ft

"He followed the fish down 8 feet.

Now we need to subtract 8ft

His new position is:

Position = -28ft - 8 ft = -36 ft

"Then he followed the fish up 27 feet."

Now we add another 27 ft.

The final position will be:

Position = -36ft + 27ft = -9ft

Then the final position of the scuba diver is -9ft, that means that he is 9 feet below the surface.

hi, i am not sure about this one but i think its d,

hope this !

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this