In a drill, Mark gives Fred a 45 meter head start. After t seconds, Fred is a distance 5t +45 from the starting line andMark is a distance of 6t from the starting line. How far ahead of Mark is Fred after t seconds?

After t seconds, Fred is far away from Mark by (45-t).

Step-by-step explanation:

Given: Mark gives Fred a 45meter head start.

After t seconds, the distance of  Fred from the starting point = 5t+45

The distance of Mark from the starting point = 6t

Now, Distance between Fred and Mark after t seconds = Location of Fred - Location of Mark

= (5t+45)-6t

= 5t+45-6t

= 45-t

Hence, After t seconds, Fred is far away from Mark by (45-t).

(-5,-28)

i graphed to on desmos.