The sum of twice a number and 4 times another number is 4. The difference of the numbers is 5. Find the numbers(help a sis out)

1st number = 4

2nd number = -1

Step-by-step explanation:

Let n = 1st number

Let m = 2nd number

2n + 4m = 4

n - m = 5

Substitu method, let n = 5 + m

2(5+m) + 4m = 4

10 + 2m + 4m = 4

6m = -6

m = -1

find n:

n - (-1) = 5

n + 1 = 5

n = 4

3.how is solving radical equations different than solving linear equations?

step-by-step explanation:

its 60

4 x 12 = 48

3 x 4 = 12

48 + 12 = 60

yeeeet