Find the equation of a line which has: slope of -2 and
crosses the y-axis at 5

in slope-intercept form

y = -2x + 5

Step-by-step explanation:

Recall that slope-intercept form is y = mx + b where m is the slope and b is the y intercept

In this case our slope is m = -2

and, line crosses y-axis at 5 which is b = 5

thus, y = -2x + 5

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3

i’m here for points.