Assume that x = x(t) and y = y(t). Let y = x^2 + 6 and
dx/dt=4 when x=1
Find dy/dt when x = 1

= 8

Step-by-step explanation:

Given:

x = x(t) and y = y(t)

Let y = x² + 6

By differentiating the given equation with respect to t,

Since, when x = 1

[By substituting the values of and x = 1]

= 8

welll its a very hard question but ill

step-by-step explanation:

first you take the 6 dollars and add 10 to it then add the 50 to that then multiply by 8 with xy and your answer will be

hope this

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead