Subtract equation two 3 digit numbers with different hundreds digits and a difference of less than 100

690 - 595

Step-by-step explanation:

As we know that representation of a 3 digit number = xyz

where x 0

z is at ones place

y is at tens place

x is at hundred place

As, we have to subtract two 3 digits numbers with different hundred digits

So, Let

The hundred digit of first number be 6

The hundred digit of second number be 5

∴

Assume first number with hundred digit 6

Let the number be - 690

Now,

Assume second number with hundred digit 5

Let the number be - 595

Now,

We will check that the difference between both the numbers are less than 100 or not

Now,

690 - 595 = 95 < 100

It satisfies the condition

So, the equation becomes 690 - 595

it would be 4 over -2 divided by -1 over 3.

if you want a solution it would be 4

you flip it so it would be 4/-2 divided by 3/-1 then it would be 12/3 and you would simplify it to 4

the cost function, c(x), is the total cost of manufacturing x units of the product. how many units must the company produce and sell if they wish to make a b. if the company produces and sells 2000 units, would they obtain a profit or loss?