(1). There are always 4 bars of chocolates, left when box of chocolates shared
equally among 8, 10, or 12 children.
Find the smallest number of chocolates
in the box,

The smallest number of chocolates in the box is 124.

Step-by-step explanation:

There are always 4 bars of chocolates left in the box when they are share equally among 8, 10, or 12 children.

This means that the smallest number of chocolates in the box is 4 added to the least common multiple of 8, 10 and 12.

LCM(8,10,12).

We factore them by prime factors until all are 1. So

8 - 10 - 12|2

4 - 5 - 6|2

2 - 5 - 3|2

1 - 5 - 3|3

1 - 5 - 1|5

1 - 1 - 1

So

lcm(8,10,12) = 2*2*2*3*5 = 8*15 = 120

Adding 4: 120 + 4 = 124

The smallest number of chocolates in the box is 124.

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step-by-step explanation:

welll its a very hard question but ill

step-by-step explanation:

first you take the 6 dollars and add 10 to it then add the 50 to that then multiply by 8 with xy and your answer will be

hope this