Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. If they conduct rounds at

the same time After how many minutes they will rounds together again?

They will do rounds together again in 11 minutes and 40 seconds.

Step-by-step explanation:

Security A rounds every 2 minutes and 20 seconds in the gate 1.

That is, after 2*60 + 20 = 120 + 20 = 140 seconds.

Security B rounds every 1 minute and 40 seconds in the gate 2.

That is, after 1*60 + 40 = 60 + 40 = 100 seconds.

After how many minutes they will rounds together again?

First, we find this is seconds, which is the least common multiple between 140 and 100. Factoring them by prime factors:

140 - 100|2

70 - 50|2

35 - 25|5

7 - 5|5

7 - 1|7

1 - 1

lcm(140,100) = 2*2*5*5*7 = 700 seconds

They will do rounds together again in 700 seconds, which is 11 minutes and 40 seconds.

= 5

step-by-step explanation:

to find the 15th term substitute n = 15 into the nth term formula

= (- 3 × 15 ) + 50 = - 45 + 50 = 5

explanation:

step-by-step explanation: