The problem is as follows: What is the perimeter of this shape?

14 3/5

12 4/5

10 2/5

10 2/5

8 1/2

4 1/2

First I changed all the denominators to 20, as that’s the LCM of all these fractions. Then I added like normal and came up with this

58 71/20

Then I simplified and got
58 9/10

My test says that this is incorrect and that the whole number is actually 61 and the fractional part is actually something else. What did I do wrong when figuring out this problem? Thanks for the help.

i am currently in the exact same situation rn. algebra2/adv algebra is killing

step-by-step explanation:

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.

is only a line? i think so

we have three similar triangles, because each has a right angle and shares an angle.   let's write the angles in order: opposite to short leg, long leg, hypotenuse.

cab similar to bad similar to cbd

or as ratios,

ca: ab: cb = ba: ad: bd = cb: bd: cd

we also know

ac = ad + cd

(ad+cd): ab: cb = ba: ad: bd = cb: bd: cd

(ad+cd)/cb=cb/cd

we have cb=6, ad=5 and seek x=cd.

we reject the negative root and conclude x=4

answer: 4