The Crews family went on a day trip to Nashville. For lunch they paid $7.50 for each adult meal and $5 for each child meal for a total of $65. For dinner the family paid $10.50 for each adult meal and $5 for each child meal for a total of $77. How many adults and how many children were on the trip?

Number of adult were on the trip = 4

Number of child were on the trip = 7

Step-by-step explanation:

Let the Number of adult were on the trip = x

Let the Number of child were on the trip = y

As given,

For lunch they paid $7.50 for each adult meal and $5 for each child meal for a total of $65.

⇒7.50x + 5y = 65            ...........(1)

Also,

For dinner the family paid $10.50 for each adult meal and $5 for each child meal for a total of $77.

⇒10.50x + 5y = 77            ...........(2)

Now,

Subtract equation (2) from equation (1) , we get

10.50x + 5y  - ( 7.50x + 5y ) = 77 - 65

⇒10.50x + 5y  - 7.50x - 5y  = 12

⇒10.50x - 7.50x  = 12

⇒3x = 12

⇒x = = 4

⇒x = 4

Now,

Put the value of x in equation (2) , we get

10.50(4) + 5y = 77

⇒42 + 5y = 77

⇒5y = 77 - 42

⇒5y = 35

⇒y = = 7

⇒y = 7

∴ we get

Number of adult were on the trip = x = 4

Number of child were on the trip = y = 7

been looking for the answer havent been able to find it   but good luck with it

a) 0

step-by-step explanation:

i^413 x i^0 = 0 as any number multiplied by a zero is

happy to

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